++ 50 ++ y=e^x y=x^2-1 x=-1 x=1 212343

Here y=2x/(1x^2) Make sense So multiply both side by (1x^2) a quadritic equation will form in which cofficent of x^2 will be y and that of x will be 2 And constant will be 2 For x to be real D greater than or equal to zero So D=2^2–4y^2≥0 now Y^ 1 Alpha identifies it as Legendre's equation and gives the solution y(x) = c1x c2( − x(log(1 − x) / 2 − log(x 1)) − 1) It offers step by step if you have the right account Share answered Jul 19 ' at 1348 Ross Millikan2xy=1 Geometric figure Straight Line Slope = 2 xintercept = 1/2 = yintercept = 1/1 = Rearrange Rearrange the equation by subtracting what is to the right of the

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Y=e^x y=x^2-1 x=-1 x=1

Y=e^x y=x^2-1 x=-1 x=1-Equations Tiger Algebra gives you not only the answers, but also the complete step by step method for solving your equations 1/x/1/y so that you understand better As you have x2 then 1 x2 will always be positive So y is always positive As x becomes smaller and smaller then 1 1 x2 → 1 1 = 1 So lim x→0 1 1 x2 = 1 As x becomes bigger and bigger then 1 x2 becomes bigger so 1 1 x2 becomes smaller lim x→±∞ 1 1 x2 = 0 build a table of value for different values of x and calculate the

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Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator Here's how x• (y1)• (y1) —————————————— • xy = 0 • xy xy Now, on the left hand side, the xy cancelsVariation of Parameters Consider the linear differential equation {eq}y''b(x)y'c(x)y=f(x) {/eq} with general solution to the homogeneous equation of {eq}y_c=C_1y_1(x)C_2y_2(x) The answer is =(xe^x)/(1x)^2 We need the differentiation of a quotient (u/v)'=(u'vuv')/v^2 Here, u=e^x, =>, u'=e^x v=1x, =>, v'=1 Therefore, dy/dx=(e^x(x1)e^x

This problem has been solved!Y= (x1) (x1) (x3) Simple and best practice solution for y= (x1) (x1) (x3) equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us If x^2 xy y^3 = 1, find the value of y" at the point where x = 1 Boost your resume with certification as an expert in up to 15 unique STEM subjects this summer

Steps for Solving Linear Equation y=2x1 y = 2 x − 1 Swap sides so that all variable terms are on the left hand side Swap sides so that all variable terms are on the left hand side 2x1=y 2 x − 1 = y Add 1 to both sides Add 1 to both sidesAxis of Symmetry x = −1 2 x = 1 2 Directrix y = −5 2 y = 5 2 Select a few x x values, and plug them into the equation to find the corresponding y y values The x x values should be selected around the vertex Tap for more steps Replace the variable x x with − 1 1 in the expression If xy = ex y, then prove that dy/dx = (log x)/(1 log x)2 Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queries

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33 Rewrite the two fractions into equivalent fractions Two fractions are called equivalent if they have the same numeric value For example 1/2 and 2/4 are equivalent, y/ (y1)2 and (y2y)/ (y1)3 are equivalent as well To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective MultiplierSimple and best practice solution for 1/x1/y equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t# log a^n = nlog a# #ln x= y1# #ln x 1 = y# Step 3 Change #y# to #f^(1)(x) # #f^(1

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Free derivative applications calculator find derivative application solutions stepbystepClick here👆to get an answer to your question ️ If e^y (x 1) = 1 , then show that d^2ydx^2 = (dydx)^2 Given #y= e^(x1)# (this is a onetoone function) Step 1 Switch #x# for #y# and #y# for #x# like this #color(red) x= e^(color(blue)(y)1)# Step 2 Begin to solve for #y# Take #ln# of both side #ln(x) = lne^(y1)# Use the properties of log #ln e= 1#;

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See the answer Show transcribed image text Expert AnswerLearn with Tiger how to do x^1y^1/(xy)1 fractions in a clear and easy way Equivalent Fractions,Least Common Denominator, Reducing (Simplifying) Fractions Tiger Algebra Solver 1 Answer Start by finding the intersection point of the two functions We also know through end behaviour of the function that y = ex will be above y = e−x So, we determine the area of y = ex in the interval 0 ≤ x ≤ 1 and then subtract the area of y = e−x in the interval 0 ≤ x ≤ 1 This can be approximated to 1086 u2

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Use the distributive property to multiply y by x 2 1 Add x to both sides Add x to both sides All equations of the form ax^ {2}bxc=0 can be solved using the quadratic formula \frac {b±\sqrt {b^ {2}4ac}} {2a} The quadratic formula gives two solutions, one when ± is addition and oneCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyAs you probably know, if the solution y(x) of that ODE has a maximum point at x=t, then y'(t)=0 Hence, the ODE tells us that in such a case we must have y(t)exp(t)=1 ===> y(t)=1/exp(t)=exp(t) Therefore, from the explicit solution y(x)=(x2)/(1

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